18x^2+3x=6

Solution for 18x^2+3x=6 equation:

18x^2+3x=6

We move all terms to the left:

18x^2+3x-(6)=0

a = 18; b = 3; c = -6;
Δ = b2-4ac
Δ = 32-4·18·(-6)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-21}{2*18}=\frac{-24}{36}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+21}{2*18}=\frac{18}{36}
=1/2
$